2023-06-22 17:11:31 +02:00
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"""Functions to parse the materials string into a list of materials that we can
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score later
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Scoreable materials are:
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* metal
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* wood
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* glass
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* resin
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* fabric
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* plastic
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I will try to match materials found into the specification into one of the
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scoreable ones. However, I found a few, like "stoneware" and "cardboard" that I
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can't fid there, they'll have to remain unscored for now
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"""
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from typing import Optional, List
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import re
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MATERIAL_MAPPING = {
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"polyester": "fabric",
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"spandex": "fabric",
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"leather": "fabric",
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"crystal": "glass",
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"hardwood": "wood",
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"plywood": "wood",
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"mdf": "wood",
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"wood": "wood",
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"steel": "metal",
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"polycarbonate": "plastic",
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"polypropylene": "plastic",
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"pvc": "plastic",
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2023-06-23 10:20:08 +02:00
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"resin": "resin",
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2023-06-22 17:11:31 +02:00
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"stoneware": "stoneware",
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"cardboard": "cardboard",
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"paper": "cardboard",
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}
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def material_classifier(material: str) -> str:
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"""I will to match materials to one of the following:
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* metal
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* wood
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* glass
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* resin
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* fabric
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* plastic
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* cardboard
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* paper
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There's a fair amount of variation in the names, so I just try to see if
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a given keyword identifying a material is found.
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If no match found, just return the input string itself.
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"""
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for key, value in MATERIAL_MAPPING.items():
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if key in material:
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return value
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return material
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def clean_material_name(material: str) -> str:
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"""Do some cleaning to material names like:
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* removing annotations found inside parentheses
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* removing mounts and percentages
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* keep the names as lowercase
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So that everything is more homogenious"""
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no_paren_annotations = re.sub(r"\(.*\)", "", material)
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no_amounts = re.sub(r"\d+%?", "", no_paren_annotations)
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return no_amounts.strip().lower()
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def parse_materials(materials: Optional[str]) -> Optional[List[str]]:
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"""Parse a string of materials as specified in raw_specifications into a
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list of standardized material names.
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Return a sorted list of unique materials for more consistency"""
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if materials is None:
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return None
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material_ls = [
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material_classifier(clean_material_name(x)) for x in materials.split(",")
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]
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return sorted(set(material_ls))
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