"""Functions to parse the materials string into a list of materials that we can
score later

Scoreable materials are:
  * metal
  * wood
  * glass
  * resin
  * fabric
  * plastic

I will try to match materials found into the specification into one of the
scoreable ones. However, I found a few, like "stoneware" and "cardboard" that I
can't fid there, they'll have to remain unscored for now
"""

from typing import Optional, List
import re

MATERIAL_MAPPING = {
    "polyester": "fabric",
    "spandex": "fabric",
    "leather": "fabric",
    "crystal": "glass",
    "hardwood": "wood",
    "plywood": "wood",
    "mdf": "wood",
    "wood": "wood",
    "steel": "metal",
    "polycarbonate": "plastic",
    "polypropylene": "plastic",
    "pvc": "plastic",
    "resin": "resin",
    "stoneware": "stoneware",
    "cardboard": "cardboard",
    "paper": "cardboard",
}


def material_classifier(material: str) -> str:
    """I will to match materials to one of the following:
    * metal
    * wood
    * glass
    * resin
    * fabric
    * plastic
    * cardboard
    * paper
    There's a fair amount of variation in the names, so I just try to see if
    a given keyword identifying a material is found.
    If no match found, just return the input string itself.
    """

    for key, value in MATERIAL_MAPPING.items():
        if key in material:
            return value
    return material


def clean_material_name(material: str) -> str:
    """Do some cleaning to material names like:
      * removing annotations found inside parentheses
      * removing mounts and percentages
      * keep the names as lowercase
    So that everything is more homogenious"""
    no_paren_annotations = re.sub(r"\(.*\)", "", material)
    no_amounts = re.sub(r"\d+%?", "", no_paren_annotations)
    return no_amounts.strip().lower()


def parse_materials(materials: Optional[str]) -> Optional[List[str]]:
    """Parse a string of materials as specified in raw_specifications into a
    list of standardized material names.
    Return a sorted list of unique materials for more consistency"""
    if materials is None:
        return None
    material_ls = [
        material_classifier(clean_material_name(x)) for x in materials.split(",")
    ]
    return sorted(set(material_ls))