59 lines
1.8 KiB
Python
59 lines
1.8 KiB
Python
"""Functions to parse the dimensions string into a dictionary that represents
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those dimenions in cm
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"""
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import logging
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from typing import Dict, Optional
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import re
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from helpers.parsers.misc import convert_units
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UNIT_CONVERSIONS = {"inches": 2.54, "feet": 30.48, "cm": 1}
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def parse_dimensions_measure(dimensions: str, measure: str) -> Optional[Dict]:
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"""Using a regex, parse a measurement out of a dimensions string
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I expect to find a value of the form `1.2 inches (W)` specifying the value,
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unit and measurement.
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Return a dictionary representing the parsed value and its unit.
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"""
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expr = rf"(?P<value>\d*[.,]?\d*)\s+(?P<unit>[a-zA-Z]*)\s+\({measure}\)"
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if match := re.search(expr, dimensions):
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match_value = match.group("value")
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try:
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value = float(match_value)
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except ValueError:
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logging.error("could not parse value `%s` as a float for a dimension")
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return None
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return {
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"value": value,
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"unit": match.group("unit").lower(),
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}
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return None
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def parse_dimensions(dimensions: Optional[str]) -> Dict[str, Optional[float]]:
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"""Parse a string representing dimensions"""
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if dimensions is None:
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return {
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"height": None,
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"width": None,
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"depth": None,
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}
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height = parse_dimensions_measure(dimensions, "H")
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width = parse_dimensions_measure(dimensions, "W")
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depth = parse_dimensions_measure(dimensions, "D")
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parsed_dimensions = {
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"height": height,
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"width": width,
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"depth": depth,
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}
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result = {}
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for key, value in parsed_dimensions.items():
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if value is None:
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result[key] = value
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else:
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result[key] = convert_units(**value, unit_conversions=UNIT_CONVERSIONS)
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return result
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